Chapter 2
Relations and Functions Class 11
Ordered pair
A pair having an order is called ordered pair
Consider (a,b). a is called first component and b is called second component.
If (a,b) = (c,d), the a = c and b = d
Eg : If (2x-3, 3y+1) = (5,7), find x and y
Ans:
Equating the first component
2x-3 = 5
2x = 5 + 3 = 8
x = 8/2 = 4
equating the second component
3y+1 = 7
3y = 7-1 = 6
y = 6/3 = 2
Also Read: Trigonometry Equations
Cross product (Cartesian Product)
Q. A × B is the set of all ordered pairs in which first element is from A and second element from B
1. Let A = {1,2,3} and B = {4,5}, write A×B and B×A?
Ans:
A×B = {(1,4),(1,5),(2,4),(2,5),(3,4),(3,5)}
B×A = {(4,1),(4,2),(4,3),(5,1),(5,2),(5,3)}
Note : If A = ⌽ or B = ⌽-, then A×B = ⌽
n(A×B) = n(A).n(B)
n(A ) = 3, n(B) = 2
n(A×B) = 3×2 = 6
n(A×A) = n(A). n(A) = 3×3= 9
n(A×A×A) = n(A). n(A) .n(A)= 3×3×3= 27
Q. A = {-1,0}. Find A×A×A
Ans :
A×A = {-1,0}×{-1,0} = {(-1,-1), (-1,0), (0,-1), (0,0)}
A×A×A = {(-1,-1), (-1,0), (0,-1), (0,0)} ×{-1,0}
= {(-1,-1,-1), (-1,0,-1), (0,-1,-1), (0,0,-1), (-1,-1,1),
(-1,0,1), (0,-1,1), (0,0,1)}
Q. A = {1,2,3}, B = {3,4}, C = {4,5}, Verify that A×(B⋂C)= (A×B)⋂(A×C)
Ans :
L H S
B⋂C = {4}
A×(B⋂C) = {1,2,3}×{4}
= {(1,4), (2,4), (3,4)}
R H S
A×B = {1,2,3}×{3,4}
= {(1,3),(1,4),(2,3),(2,4),(3,3),(3,4)}
A×C = {1,2,3}×{4,5}
= {(1,4), (1,4),(2,4),(2,5),(3,4),(3,5)}
(A×B)⋂(A×C) = {(1,4),(2,4),(3,4)}
L H S = R H S
Ans :
3x-y = 0
Put x = 1
3×1 – y = 0
3 – y = 0
Y = 3
Put x = 2, we get y = 6
Put x = 3, we get y = 9
Put x = 4, we get y = 12
Put x = 5, we get y = 15
R = {(1,3),(2,6),(3,9),(4,12)}
Domain = {1,2,3,4}
Range = {3,6,9,12}
Co domain = A
Q. Let A = {x,y,z}, B = {1,2} find the number of relations from A to B?
Ans:
m = 3, n= 2
Number of relations = 2mn
= 23×2 = 26 = 64
Q. A = {1,2,3}, B = {4,6,9}. R is a relation from A to B defined by
R = {(x,y) : the difference between x and y is odd}. Write R in roster form. Also write its domain, co domain and range?
Ans :
A×B = {(1,4), (1,6), (1,9), (2,4), (2,6), (2,9), (3,4),(3,6), (3,9)}
R = {(1,4), (1,6), (2,9), (3,4), (3,6)}
Domain = {1,2,3}
Range = {4,6,9}
Co domain = B
Q. A×A has 9 elements of which two elements are (-3,0) and (0,3). R is a Relation on A defined by R = {(x,y) : x + y = 0}. Write r in roster form
Ans :
A×A has 9 elements
A has 3 elements
A = {-3,0,3}
R = {(-3,3), (3,-3), (0,0)}
Q. A = {1,2,3,4}. R is a relation on A defined by R = {(a,b) : b is exactly divisible by a}. Write R in roster form
Ans :
A×A = {(1,1), (1,2), (1,3), (1,4), (2,1), (2,2), (2,3), (2,4), (3,1), (3,2), (3,3), (3,4), (4,1), (4,2), (4,3), (4,4)}
R = {(1,1), (1,2), (1,3), (1,4), (2,2), (2,4), (3,3), (4,4) }
Q. The figure shows a relation from P to Q.
Write the relation in roster form and set builder form
Relations and Functions Class 11
Ans :
Roster form
{(5,3), (6,4), (7,5)}
Set builder form
R = {(x,y) : x-y = 0, x∈P, y∈Q}
Functions
1. A relation from A to B is called a function if every element of A is related to unique element of B
2. Functions are generally denoted by f,g,h…
3. F(x) = y means y is the image of x or x is the pre image of y
4. Consider f : A → B . A is called domain and B is called co domain
5. The set of elements in the co domain which have pre image is called range. Range is a subset of co domain
6. Number of relations from A to B is

Fig 1 represents a function since every element in A has unique image in B
Fig 2 is not a function since 2 has more than one image and 3 has no image
Q. Find the domain and range of f(x) =
x2 – 5x + 6 = 0
a =1, b = -5, c = 6
Domain = R – {2,3}
Q. Find the domain and range of f(x) =
= y

Range = R – {1}
Previous Years’ Questions Relations and Functions Class 11

2. Find the domain and range of f(x) =












Exercise Relations and Functions Class 11







Users view